Start with the
Let's begin our investigation by observing what the function of this
equation looks like for different values of a, b, and k respectively
while holding the other two values constant.
Let r = a + cos
(2ø). The following graph shows what happens when a = -3,
-2, -1, 0, 1, 2, 3.
Notice that when a
< 0, the graph is stretched in the vertical direction, along the y
notice when a < -1, the curve intersects the x axis at |a| - 1 and
the y axis at |a| +1. When a > 0, the graph is
stretched in the horizontal direction, along the x axis. When a >1, the curve
intersects the y axis at |a| - 1 and the x axis at |a| +1. These graphs are
all centered on the origin. Notice also, that when |a| is less
than or equal to 1, the graph of the curve intersects the origin.
When b = 0, the graph is a circle. When b does not equal 0, the graph has three leaves. When b is negative the graph is symmetric about the line y = x. When b is positive, the graph is symmetric about the line y = -x.
Compare this to the graph of the equation, r = b cos (3ø), where a = 0.
The same properties of symmetry still apply from the previous example. This graph is a bit more simplistic then the last graph in that each equation only has one set of leaves. Looking back at the previous picture, several of the equations have two sets of similar leaves.
Notice when k = 0 and k = 1, the graph is a circle. When k > 1, the graph is an n-leaf rose. Again, when k is even, the graph of the equation is centered on the x axis.
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