EMT 668 - Algorithms & Computers
ASSIGNMENT 2, #6
Kimberly N. Bennekin
The following is the graph of .
i) Overlay a new graph replacing each x by (x - 4). The following is the
graph of (right) and (left).
The standard form for the equation of a parabola is
ii) Change the equation to move the graph into the second quadrant.
where (h,k) is the vertex of the parabola. To move the graph into the
second quadrant, we would have to move the vertex into the second quadrant
by making h<0 and k>0. If we write
in standard form we get ,
where the vertex is (13/4, -41/8) which lies in Quadrant IV. To move
the vertex into Quadrant II, we change the equation to ,
which moves the vertex of the parabola to (-13/4, 41/8).
The graph of
iii) Change the equation to produce a graph concave down that shares
the same vertex.
If a>0, the parabola is concave up. If a<0, the parabola
is concave down. If we take the identical
equation and change a from 2 to -2, we will flip the parabola down.
This will not change the vertex.
The graph of .