Finding x and y
by Molly McKee
 
Given three points A, B, and C.
Draw a line intersecting AC in the point X and BC in the point Y such that
AX=XY=YB
Return to Class Page
Return to EMAT 6680 Pagehttp://jwilson.coe.uga.edu/EMAT6680Su07/McKee/Molly.htmlhttp://jwilson.coe.uga.edu/EMT668/EMT668.htmlshapeimage_1_link_0shapeimage_1_link_1
Construct a point on segment AC called X.
Construct a circle using X as the center and A as the radius.
Note that since X is not a fixed point, the dimensions of the circle can change depending on where X is located on AC
gsp version6.1_files/xmovement-1.gsp6.1_files/xmovement.gspshapeimage_2_link_0
Construct a line parallel to BC which passes through X.
Find the point of intersection between this line and Circle X.
Call this point X'.
Because X’ and A are both radii of Circle X, AX=X’X.
Now construct a circle using X’ as the center and X as the radius.
Note that since the location of X’ is dependent on the location of X, the dimensions of the circle can change depending on where X is located on AC.
gsp file showing Circle X’ fluctuatingmailto:molly.mckee@gmail.com?subject=email%20subject6.1_files/x%27movement.gspshapeimage_3_link_0
Label where circle X intersects BC.  Call this Y.
Construct the line segment XY.
Now we know that AX=XY=XX'
because they are all radii of circle X.
Now we just need to position Y so that AX=XY=YB.
Construct a line parallel to XY which passes through X’.
Find the point of intersection between this line and Circle X’.
Call this point Y'.
Construct segment X'Y'.
Now we have that AX=XY=XX'=X'Y' and XY is parallel to X'Y'.
Construct  YY'.
We have created a rhombus.
A rhombus is a quadrilateral with all sides equal in length and opposite sides are parallel.
To solve the problem, we need for YB to equal XY and AX.
Notice that YY’=XY=AX.
Therefore we must make Y’=B.
Since Y’ is dependent upon X’ which is dependent upon X,
we should be able to move X along AC to find where Y’=B.
gsp versionhttp://jwilson.coe.uga.edu/EMAT6680Su07/McKee/Molly.html6.1_files/y%27movement.gspshapeimage_4_link_0
Now we have found where X needs to be positioned on AC so that AX=XY=YB.
file showing Circle X fluctuatinghttp://jwilson.coe.uga.edu/EMAT6680Su07/McKee/animation/xmovement.html6.1_files/xmovement_1.gspshapeimage_5_link_0
file showing finding where Y’=Bhttp://jwilson.coe.uga.edu/EMAT6680Su07/McKee/animation/ymovement.html6.1_files/xmovement_2.gspshapeimage_6_link_0