+ 09\0p2ca"Tpmp O@JeO\X] ;HO);AlCWB $2)7 ;HO);BlD B in ;HO);C00lD)B fk ;HO);D`00lCCV 1F Z@ ;HO);tria  B7C<7l]xgEThe center of mass of quadrilateral ABCD is point P. This is found by finding the centroids of triangles ACD,ACB, BAD, and BCD. The centroids for those are c1, c3, c2, and c4 respectively. Connecting c2c4 and c1c3, find the point of intersection. This is point P, or the center of mass for the quadrilateral. I noticed that there is a similarity, though no exactness, between the point of intersection of the diagonals of the parallelogram constructed with vertices as the midpoints of sides AB, BC, CD, and DA. Lines c1c3 and c2c4 seems to be perpendicular as are KG and FL.L.x\p`\p3T3\ EE#N#EZ1he  ;HO);jlCCVD)B?#1n  ;HO);klD)BD B?#]7  ;HO);l`00lD BCWB?Wk  ;HO);m`00lCWBCCV?#e7  ;HO);n`00lCCVD B?Wn  ;HO);ulCWBD)B?| ;HO);ElCB FlKq ;HO);FlD`B   ;HO);GlDC >Cp ;HO);KlCB#  ;HO);LC0ClCC `e ;HO);NlC߀B Eeq  ;HO);olCCVD`B? h  ;HO);plD)BCB? #7  ;HO);qlD BDC ?=e  ;HO);rlCCVCB?W  ;HO);sspace. lCWBCB? #7  ;HO);tlD BCC?W E.23  ;HO);vlCWBDC ?_e  ;HO);wlCCVC߀B?h7NGS  ;HO);x\WIN98\TEMP\Asgn7.gspclD)BCC?E]q)  ;HO);yd7O@7OT 7O0 7.gsplCWBD`B? #e7O7  ;HO);zOt 7O 7O 7O 7O, 7OsOL s 7O( 7O( 7O4 7O@ 7OHT $ 7lD BC߀B?=n  ;HO);aaNT 7O2bT (7O 7O OT 7O6 7OH 7OHlD)BCB?=Kq  ;HO );alm7lD`BCB? EqC  ;HO );ap r8_-?rea p5 = lD`BDC ?  4  ;HO );aq:vK$aI0N+ FJplDC CC?=p:  ;HO );ar.: zu"DBm 4 4:lCCCB?=   ;HO );as?Oem?UOH#DBu"DBƉC_CÁC6lDC CB?EqP?[  ;HO );atArea(Polygonp5) = lCCD`B? v{ ;HO);c4ƣ__V _ _V _ O_lDVBUT pzu ;HO);c2'?'? __lCVBLQ ;HO);c3'?'? _b_lCB  ;HO);c1'?'? _b_lCC ns  ;HO );UC 4 ::4 :undeflC@B #"oy{  ;HO);ab @O ZdlCVBDVBUT?$%KHn  ;HO);ac@a8HـA\|u@HA8!|aN |lCC CB?&'rw.A ;HO);Pƣ__V _ _V _ [klCzB)*