GSPk FI[capmdt6;" BSzTP5"$M;n]CC t8= BOC~C  ts@ The blue triangle was constructed as a kind of test structure. I wanted to see what the relationship was between the medians and the triangle so I could begin my construction with just the medians. The most significant thing I saw was that the medians intersect each other such that each median is divided into two segments, one twice as long as the other. So, I began by finding the divisions on each given median so that I had the desired 2 to 1 ration. To do this, I first tri-sected all the segmentsThen I placed all the medias together on one concurrent point by using radii equal to my desired length. Then, I had my medians intersected at a concurrent point. From there, however, I got stuck. I had trouble figuring out how to construct the sides so that medians would bisect the legs of the triangle and so that the legs would be parallel to the opposite side of that triangle's medial triangle.tej( AYP > ~-$?E CC t AT(^-irtHK>Sv `BCC t AQsCC t  AK $ X*pk X 4#jh ^k |CDC t AEUC.C t- 2 W X`:($:LxrM@D D t+0  N3(osWr~ r~C:\ATI@KDC t L%Qo6  MtCC:tCCgDC;knCtCC;P!ni$CHDB t9>  L;x  M  4E . ClB t=B H$vD1 XpOTDC  t80F  v$F(FF(FF~"|F&F"FF"F&FF&FF~vЎ@KDCClB? tK0  uF&DȊ͈n:u&D :ut$&& ^"&t*F&DȊ͈nHDB@KDC? t8%QX0  tC CӸC{CC; ; ;;{CCtCC|;ClBHDB? trw6  QCCA@#DB ;N 6DlC tlBqG  PW   p1! B|DB t&+ OIDuC  tkA0  bdDB@KDC?  tqK%  acTDlCHDB?  t8+q  z24€w–r>?(   ;ClBIDuC? t  Vj+DUU7C t$}8A m3   ,k UUUUU OV = Distance(O to V) = t{# m2EXE VL = Distance(V to L) = t /: m4ppppppppppppp {D:VL}{OV} = $Distance(V to L)/Distance(O to V) = D Comic Sans MSArial(;