Assignment 8

Jonathan Lawson

In this exploration we will look at the triangle ABC and its orthocenter, H, and prove this equation

*
*

where D, E, and F are the feet of the perpendiculars from A, B, and C respectfully. See picture below

So we first begin with the equation

(where is indicative of the area of these triangles). By dividing the equation we get

At this point we will convert the area of these triangles to equivalent measures using the segments that are labeled within the triangle. The picture will be divided into the three triangles and of course the whole triangle is ABC.

So our equation becomes

which proves our stated equation.

From the above equation it is easy to prove the following statement

First we will start with these stated equations from the triangle diagram above

*AH
*+ *HD* = *AD*,

*BH*
+ *HE* = *BE*,

and
*CH* + *HF* = *CF*.

Divide
the first equation by *AD*, divide the second equation by *BE*, and
divide the third equation by *CF*, we get the following

Adding these three equations gives

and since , then we now have

which proves the equation stated at the beginning.

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