By Nami Youn

**Write-up
#10**

Introduction

A parametric curve in the plane is a pair of functions

Where the two continuous function define ordered pairs (x,y). The two equations are usually called the parametric equations of a curve.The curve is dependent on the range of t.

In this write-up, I will investigate the parametric equations and variation of these equations.

x = acos(t)

y = bsint(t) for
various a and b

1. For a equals
to b,
**x = acos(t)**
**
y = bsint(t)**

First, let's consider the case a, b > 0.

a = b = 1 (purple), a = b = 2(blue), a = b = 4(green)

We can notice that the all graphs are the circles centered
at the origin(0, 0). Specially, for a = b = 1, the graph is the unit circle.
The radius are 1, 2, 4 respectively, the same value as a =b.

So, we can see that the value of a=b decides the
radius of the circle, the graph of x = cost (t), y = sin(t). Also, as the
value of a=b increases, the radius of the circle is greater.

Next, let's consider the case a, b < 0.

a = b = -1 (purple), a = b = -2(blue), a = b = -4(green)

We can get the same graphs as the case a, b>0. Notice
that the all graphs are also the circles centered at the origin(0, 0).
Specially, for a = b = -1, the graph is the unit circle. The radius are
1, 2, 4 respectively, the same as the absolute value of a =b.

So, we can see that the absolute value of a=b decides
the radius of the circle, the graph of x = cost (t), y = sin(t). Also,
as the absoulte value of a=b increases, the radius of the circle is greater.

We have another result through investigation of the graphs. If the absoulte values of a and b of two equations are the same, the two graphs are exactly equal. For example, the graphs of both x = cost (t), y = sin(t) and x = -cost (t), y = -sin(t) are the same.

2. For
a does not equal to b,
**x = acos(t)**
**
y = bsint(t)**

Next, let's consider the case the absolute value of a < the absoulte value of b

Let fix a = 1 varing the value of b.

b = -2(purple), b = 3(blue), b = 5(green)

It is obvious that the graphs are ellipes. The center
of the all ellipes is the origin(0, 0).

Also, we can notice that the graph is enlongated along
the y-axis as the absoulte value of b increases.

Next, let's consider the case the absolute value of a > the absoulte value of b

Let fix b = 1 varing the value of a.

a = -2(purple), a = 3(blue), a = 5(green)

We have the different shape of ellipes. But, the center
of the all ellipes is still the origin(0, 0).

We can notice that the graph is enlongated along the
x-axis as the absoulte value of a increases.