Assignment 4: What is the Euler Line?

By: David Drew

EMAT 6680, Jim Wilson

As a current student and a future teacher there are several things that I feel I should know like the back of my hand. And when I run across a term or certain equation that I don’t know or understand then I like to explore it until I feel I have mastered it. In this case I would like to take part 5 of assignment 4, and adapt it to fulfill my curiosity. I have heard the buzzword ‘Euler Line’ several times in my first few classes in Graduate School but I never knew what it was. So without anymore caution I will now explore the ‘Euler Line’.

We start with any triangle constructed from points A, B, and C. As shown below.

Now we make the medians of each segment so we have points D, E, and F bisecting segments AB, BD, and AC, respectively.

Now we’ll begin to create to Euler Line. Before we can say that we’ve constructed the Euler line we need to find three very important points inside the triangle: the centroid, the circumcenter, and the othocenter. These three points are critical and intriguing, but this is an assignment about the Euler Line and thus I will only give a small definition of each of these as well as a picture for visual effects.

Centroid: A line connecting a vertex with the opposite side’s midpoint is called a median of a triangle. If we construct the three medians then we can see that they all intersect at a certain point. This point, as you’ve guessed, is the centroid. It’s represented by the point G.

Circumcenter: The lines through each median D, E, and F parallel to their corresponding segments intersect at a point O. This point represents the center of the circle that the three point all lie on. This is known as the circumcircle.

Orthocenter: An altitude of the triangle is a line drawn through a vertex perpendicular to the side of the triangle opposite the vertex. There are three altitudes: one is AD perpendicular to the side BC, the second is BE perpendicular to the side CA, and the third is CF perpendicular to the side AB. The altitudes of a triangle meet at a point, called the orthocenter, denoted here by H.

We have all the ingredients for the Euler line so let’s see the final product when the centroid, the circumcenter, and the orthocenter are all together.

As we can see the three points seem to lie on one distinct line. This line is the famous Euler Line. Here’s final picture with the line connecting all the points.

Here’s a quick and simple proof of the Euler line. We’ll do this proof and then say some things about Euler after and call it quits on our discussion.

Proof: We one last picture to demonstrate our theory about the Euler line. We are just going to include the midpoints of each segment of our original triangle.

We’ll take a closer look at triangles ACB and EDF. As you can see triangles ACB and EDF are similar, and EDF is half the size of ACB. Concordantly DE is parallel to AC, DF is parallel to BC, and EF is parallel to AB since each of the points D, E, and F are all midpoints of their corresponding segments. These triangles are called parallel triangles or homothetic triangles if you wish to use the more scholarly term. We also know from above that AE, CD, and BF all meet at point G. But we also know that ACB is a scale of EDF with a factor of -2 over G. This means that if you take a point T on EDF, measure the distance TG, multiply TG by 2 and go that distance on the opposite side of G, you’ll get the corresponding point S on ACB.

Now EO is perpendicular to BC, from our construction of O above, but since BC and DF are parallel then EO is perpendicular to DF also. In this way we can tell that O is the orthocenter of EDF. And thus we have an interesting observation: the circumcenter of ACB is the orthocenter of EDF. Now we can see what happens when we multiply the orthocenter of EDF over G with a factor of -2. The solution must go to the orthocenter, H, of ACB. So when we perform this scale of our point O we get H of the big triangle ACB therefore all three points must be on one line, Euler’s Line.