**Again, we begin with the equation**

**It is important to note that the vertex
of this equation lies in Quadrant III. The vertex (-0.75, -5.125)
has a negative x value as well as a negative y value. In order
to "move" the graph into Quadrant II, the vertex needs
to keep a negative x value but the y value needs to be positive.
For simplicity, we will not change the x coordinate of the vertex
with our translation to move the graph. Let us replace the current
y coordinate of the vertex with +4. Thus, the new equation is**

**Let us now refer to the graph**

**We have successfully translated the vertex
into the second quadrant. Now, we must decide if this indeed qualifies
as a move into the second quadrant. What happens if we also alter
the x coordinate of the vertex . Let's try**

**This is a horizontal shift to the left of
11.75 units.**

**Here, we see that the graph is unquestionably
located in the second quadrant.**

**Our final translation vector is <-11.75,
9.125>.**