Investigate for a = b, a <
b and a > b.
We first look at integer values for k when
In all the case above, a = b (they are both 1). We notive
that the integer valu of k gives us the number of curves (or leaves) of
each graph. Since a = 1 and b = 1, the length of each curve is 2 (1 + 1).
In these graphs, a < b. We kept k at the same value
5, so each graph has 5 curves. But having different values of a and b gave
us each double curves. One curve has length a + b and the other has b -
Finally, we look at the case where a > b. We notice
that we still have the same number of leaves, but each leaf is not totally
section off. The main length is still a + b, but indention is a - b.
Second, we look at values of k = 1/2 , 3/2 , 5/2 , ... when .
When a = b in these graphs, we get a curve with an inward
loop. The value of k still gives us the number of leaves, but it is the
numerator that tells us this.
The same thing also happens when a < b. We get a double
figure, but the second leaf is between the first (coming from the demoninator).
Similarly, when a > b, we get curves that are not fully
Finally we look at values of k = 1/3
, 2/3 , 5/3, ... when .
We see that this case gives us 3 loops ( the denominator
of k) for each leaf ( the numerator of k)
If a < b, we have the leaves doubled.
If a > b, the curves ar not fully closed.