Assignment 8
Altitudes and Orthocenters

by Kelli Nipper

After constructing the orthocenters for the four triangles, it was obvious that for any triangle:

Click Here to view the orthocenter's position for various triangles.

Next, I constructed the circumcircle for the four triangles.

Connecting the centers of triangle HAB, HAC, and HBC creates a triangle congruent to triangle ABC.

This is obvious since AB is congruent to DE; BC is congruent to EF; and CA is congruent to DF. These triangles are translations of each other.

After constructing the nine-point circle for triangles ABC, HAB, and HBC, I found that they were all the same circle. This is true because:

I found that the midpoints of the sides of triangle ABC(Yellow) are the same as the midpoints of the segments connecting the vertices of the orthocenter (Point C) of triangle HAB. (and vice versa giving us 6 of the 9 mandatory points. The final 3 points(Red) come from the feet of the altitudes which coincide for the 4 triangles.

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