Family of Hyperbolas

by

Helene Chidsey and Lou Ann Lovin

In this investigation we looked at the family of curves formed by the equation,


(equation 1)

where we varied a, b, or c and held the other two constant. We chose to use Algebra Xpresser for this investigation.



First, we let a = b = 1 and c = 0, 0.5, 1, and 2.

c=0 (red)
c=0.5 (green)
c=1 (blue)
c=2 (tan)

As c increases, the hyperbolas move away from the origin, and they become more narrow.


Below we overlayed the graphs of x-1=0 (purple) and y-1=0 (green) on the previous graphs.

These two lines (purple and green) look like the asymptotes. We investigated further by solving the initial equation for y and then x and graphing the resulting equations. Solving for y, we obtain the equation,


(equation 2)

Again, we allowed a=b=1 and c=0, 0.5, 1, and 2. See graphs below.

c=0 (red)
c=0.5 (green)
c=1 (blue)
c=2 (tan)

The tan vertical line is x-1=0 and acts like one of the asymptotes of the family of hyperbolas. If we look at equation 2, we see that it is not defined when x-1=0, since we cannot have a zero in the denominator. So the hyperbolas get closer and closer to the line x-1=0, but never reach it (i.e., the definition of an asymptote).


Solving for x, we get the equation,


(equation 3)

Again, we allowed a=b=1 and c=0, 0.5, 1, and 2. See graphs below.

c=0 (red)
c=0.5 (green)
c=1 (blue)
c=2 (tan)


The tan horizontal line is y-1=0 and acts like the other asymptote of the family of hyperbolas. If we look at equation 3, we see that it is not defined when y-1=0, since we cannot have a zero in the denominator. So the hyperbolas get closer and closer to the line y-1=0, but never reach it (i.e., the definition of an asymptote). (Further investigations will be done only with equation 1.)


Next we let a=b=3 and again let c= 0, 0.5, 1, and 2.

c=0 (red)
c=0.5 (green)
c=1 (blue)
c=2 (tan)


From the discussion above, we assume that x - b = 0 and y - a = 0 are the asymptotes (where a = b = 3 in this case). The graph below verifies this.



Below we examine graphs for a = b = 1, a = b = 3 , a = b = 4 ,and c = 0.

a = b = 1 (green)
a = b = 3 (red)
a = b = 4 (blue)

As a and b increase, the upper hyperbolas move away from the origin, but the lower halves still go through the origin. Also, the hyperbolas widen as a and b increase.


We have examined positive values of a and b, so next we looked at a = b = -1 and
c = 0, 0.5, 1, and 2.

c=0 (red)
c=0.5 (green)
c=1 (blue)
c=2 (tan)



For thoroughness, we then looked at a = b = -3 and c = 0, 0.5, 1, and 2.

c=0 (red)
c=0.5 (green)
c=1 (blue)
c=2 (tan)

It appears that negative values of a and b shift the hyperbolas down and to the left, while smaller values widen the hyperbolas. Thus when a and b are positive, larger values widen the hyperbolas, and when a and b are negative, smaller values widen the hyperbolas. In general, if the absolute value of a and b increases, the hyperbolas will widen. Also as the absolute value of a and b increase, the lower halves of the hyperbolas move away from the origin.


Next we looked at a = b = 1, while c = 0, -0.5, -1, -2.

c=0 (red)
c=-0.5 (green)
c=-1 (blue)
c=-2 (tan)

The blue lines (where c = -1) look like asymptotes to these hyperbolas. However upon closer inspection of this equation we saw that,

xy = x + y - 1 =====> (x-1)(1-y) = 0,

which is defined everywhere. Since the asymptotes of these hyperbolas are x-1=0 and 1-y=0 (see reasoning above), we see that the blue lines lie on top of the asymptotes.

We also noticed that when c=-2 (the tan lines, above) the hyperbola moves into the second and fourth quadrants (using the blue lines as our axes). At first we suspected that the hyperbolas were just reflections of each other (about x-1=0 or y-1=0) when |c| equaled the same number. We tested out conjecture by graphing the hyperbolas where c = -2 (red) and c = 2 (green) and (x-1)(y-1)=0 (blue).

Obviously they are not reflections of each other since the red hyperbola (c=-2) is narrower than the green hyperbola (c=2). Also the red hyperbola approaches the lines x-1=0 and y-1=0 faster than the green hyperbola. However, they do share the same asymptotes.


Next we let a = c = 1 and b = 0, 0.5, 1, and 2.

b=0 (red)
b=0.5 (green)
b=1 (blue)
b=2 (tan)

The hyperbolas move to the right, as b increases.


Next we let a = c = 3 and b = 0, 0.5, 1, and 2.

b=0 (red)
b=0.5 (green)
b=1 (blue)
b=2 (tan)

As a and c increase, the hyperbolas widen as they move away from the origin.


Next we graphed a = c = -1 and b = 0, 0.5, 1, and 2.

b=0 (red)
b=0.5 (green)
b=1 (blue)
b=2 (tan)





Before we comment on how negative values of a and c affect the hyperbolas, look at a = c = -3 and b = 0, 0.5, 1, and 2.

b=0 (red)
b=0.5 (green)
b=1 (blue)
b=2 (tan)

It appears that negative values of a and c flip the hyperbolas about the origin, and smaller values widen the hyperbolas. Thus when a and c are positive, larger values widen the hyperbolas, and when a and c are negative, smaller values widen the hyperbolas as well. In general, as the absolute value of a and c increases, the hyperbolas widen. Also as the absolute value of a and c increase, the lower halves of the hyperbolas move away from the origin.


Next we looked at a = c = 1 and b = 0, -0.5, -1, -2.

b=0 (red)
b=-0.5 (green)
b=-1 (blue)
b=-2 (tan)




Here only one of the blue lines (where b = -1) looks like an asymptote to these hyperbolas, namely the horizontal line y-1=0. Since we varied the coefficient of the y-term, the hyperbolas shift to the left and thus cannot have the same vertical asymptote. See the following graph to verify.

a = c = 1
b=0 (red)
b=-1(green)
b=-2 (blue)
b=-3 (tan)
b=-4 (purple)



Next we let b = c = 1 and a = 0, 0.5, 1, and 2.

a=0 (red)
a=0.5 (green)
a=1 (blue)
a=2 (tan)

As a increases the lower hyperbolas move upward and slightly to the left, while the upper hyperbolas move away from the orgin.


We then let b = c = 3 and a = 0, 0.5, 1, and 2.

a=0 (red)
a=0.5 (green)
a=1 (blue)
a=2 (tan)

As b and c increase, the upper hyperbolas widen as they move away from the origin, whereas the lower hyperbolas move upward and slightly to the left.


Next let b = c = -1 while a = 0, 0.5, 1, and 2.

a=0 (red)
a=0.5 (green)
a=1 (blue)
a=2 (tan)




Before we comment on how negative values of b and c affect the hyperbolas, look at b = c = -3 and a = 0, 0.5, 1, and 2.

a=0 (red)
a=0.5 (green)
a=1 (blue)
a=2 (tan)


It appears that negative values of b and c flip the hyperbolas about the origin and smaller values widen the hyperbolas. So when b and c are positive, larger values widen the hyperbolas, and when b and c are negative, smaller values also widen the hyperbolas. In general, if the absolute value of b and c increases, the hyperbolas widen. Also as the absolute value of b and c increase the lower halves of the hyperbolas move away from the origin.


The graph below is for b = c = 1 and a = 0, -0.5, -1, -2.

a=0 (red)
a=-0.5 (green)
a=-1 (blue)
a=-2 (tan)


Here only one of the blue lines (where a = -1) looks like an asymptote to these hyperbolas, namely the horizontal line x-1=0. Since we varied the coefficient of an x-term, the hyperbolas shift down and thus cannot have the same horizontal asymptote. See the following graph to verify.

b = c = 1
a=0 (red)
a=-1(green)
a=-2 (blue)
a=-3 (tan)
a=-4 (purple)


In conclusion, we looked at the graphs (x-b)(y-a)=k (where k is any real number). Expanding

(x-b)(y-a)=k

gives us the following equation: xy -ax - by +ab=k.

Solving for xy, we obtain our original equation

xy = ax + by + k - ab where c = k-ab.

To investigate we let k = 0, 1, 2, 3 and a = b = 1.

k= 0 (red)
k = 1 (green)
k = 2 (blue)
k = 3 (tan)

Again we graph, letting k = 0 , -1, -2, -3 and a = b = 1.

k= 0 (red)
k = -1 (green)
k = -2 (blue)
k = -3 (tan)

From these two pictures, it appears that if k=0 we get perpendicular lines. If we look closely at the general equation xy = ax + by + k - ab, when k = 0, c = -ab. So for our specific equation where
a = b = 1, we have

xy = x + y - 1,

which factors into

(x-1)(y-1) = 0.

When we graph this equation, we get the perpendicular lines x-1=0 and y-1=0.

If k0, then c = k - ab and we get another set of hyperbolas. For our specific equation where
a = b = 1, we have

xy = x + y + k -1.

Thus c = k - 1, and for the various values of k0, we get sets of hyperbolas.

So we see that as we vary a, b, or c and hold the other two constant, we generate a family of hyperbolas that change position and orientation as well as width. Thus, using technology such as Algebra Xpresser enables students to more easily investigate families of curves in depth.


Return to Final Page.