\Vk capm*@`KT@k Z 2Gd}As in problem #2, you are given a 90 degree angle (HJG) so the area is calculated by multiplying 16 by 7 to get 112 and then taking half of that gives you 56 square units. Is there anything wrong with this solution?@V`VŤJJ<[ 2Gd} .As in proble.<dj@  uSXChij`q0jijq0HCk: 2Mb~Since you know the angle FED is 90 degrees, EF is perpendicular to DE so you can find the area by multiplying 4 by 11 and the taking half. The answer then is 22 square units. Notice this will work if you chose EF or DE as the base.ijq0ikq0ik `q0ihZN <.Ġ.1HRYou cannot find the area because you do not have a perpendicular hieght to a base.Ā.00Ϩ.Ā.PϨ.Ā.ĠMrRw ! AH-@-Ϩ  --(BB-! B0-@-0- -CRC6 uz! C`0 CB 7<!!  D. AC.!  Ec+..@. cb0-I.Y\CC fBkG!  FϨ P. .Ϩa. cCC ! G.)c.CCfk ! H`0C$D fk! ICD Lq ! 12 units I`I)=I0.g@NI005>dEZBBCRC6?e%H t ! 15 units I`I)=I0.g@NI005>dEZCRC6CB?/ 'Lqz ! 24 units I`I)=I0.g@NI005>dEZCBBB??RQi'Otg ! p1Dbggp qb g C0e_T?CBCRC6BB6d !  11 units I`I)=I0.g@NI005>dEZACCC?,5v 6kG  !  15 units I`I)=I0.g@NI005>dEZACCC?ޭޭ$ eG. !  4 units I`I)=I0.g@NI005>dEZCCCC?8 " }Z   m1_Tm00n ip I m{!:A}FED = '0(2X0'0$x@@w'0= OŰI@!`*((=  K@w3p(ŰI@!`*((I߲(5( =rwI@|66ŰI@8 Angle(FED) = BIw88ŰI@9I߲I8I߮7I:I@Student.Foldersv(5(  "6I߲@.H5II `9Tr I987IvI@Gtriangl@/'`p".I@2`$`I v)J%)7 h 2`I)J%)!` j2`@7'`2X02`II@!`*2`'0(2X0'0$x@ 9E~ !  p2Db~p~0HHw _@?CCCCAC k@ ! 9 unitsEp-ΐITIaI0g>ZI00@)4CCC$D?c+߶  k ! 16 units I`I)=I0.g@NI005>dEZCCCD?4e ek ! 12 units I`I)=I0.g@NI005>dEZCDC$D?.  i Aud ! p3omated Tasks Calculator ChooserControl Panelso?CDC$DCC ' !  sFPϨ.@0C^C@BD9`? .H! J.GHHc.H00.CKD`k ! 7 units I`I)=I0.g@NI005>dEZCKD`C$D?ɰw