## Solution Strategy

Finding an expression for c in terms of a and b can ignore the requirement for integer values. Once we have an expression for (1) we can use it to search for integer values  of a, b, and c.
Must the point of tangency of the circumcircle to DE be at the midpoint? Why?
Draw in segments FA, FC, and FB.

Let the lengths of the sides AF and BF be of length n.   Can you solve for n in terms of c?Using the Law of Cosines, from triangle ABC we get

Note that angle AFC and angle ABC subtend the same chord. Therefore they are equal. Likewise angle BFC and angle BAC subtend the same chord and therefore they are equal. That is, the measure of Angle AFB is the same as the measure of Angle A plus the measure of Angle B. Now, (angle measures) A+B = 180 - C.

Using the Law of Cosines, from triangle AFB, we get
or
But angle A + B = 180 - C, so

From triangle ADF, the Pythagorean relation would give

Therefore
Substituting in the previous equation gives
Divide both sides to get

Substituting in the first Law of Cosines equation from triangle ABC,
gives

Thus c is this function of a and b, whether or not the values are integers. The integer values are clear, however, and if (a,b,c ) satisfies the equation, then so does (ka,kb,kc).

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