One Solution

(a)  The sublime triangle is an isosceles triangle with base angles and the angle opposite the
base is . Let triangle ABC be a sublime triangle with base BC, and construct the angle bisector of angle C produced to its intersection with AB at D. Let DB = b and BC = a.

Then triangle CDB is similar to triangle ABC and CD = a, AD = a, AB = a + b, AC = a + b. The similarity allows the equation and the ratio a/b is the golden ratio
the solution to the equations or .


(b)  Angle DCB is and using the law of cosines we can write

Angle CDA is and using the law of cosines we get