Clay Kitchings :: EMAT 6600 :: Minimum of

 

 

Use the AM-GM inequality to show that the minimum of  is 2. 

 

AM-GM Inequality:      

 

Let a = 1/x and b = x

 

Apply AM-GM Inequality

 

 

 

 

 

 

 

Now for the Òwith equalityÓ part:  1/x = x implies x =1 or -1.  The negative value does not satisfy the above inequality, but x=1 satisfies it. So letÕs calculate f(1).  f(1) = 1/1 + 1 = 2.  So, this value will always be larger than or equal to 2, so therefore the minimum of the function is indeed 2.