1

 

 

Gregory Schmidt                                                                                                    

Write up #1                                                                                                      

Composition of the

Logarithmic and Exponential

 Functions

 

 

Problem: Let  and

Consider:

 

(i)            

(ii)          

(iii)         

(iv)         

 

 

 

We will explore the graphs of our new functions, and explore the changes in the domains and ranges. 

 

First we consider the graphs of  and .

 

 

 

                                         (1)

 

 

We see immediately, that  and .

 

We notice that  appears to remain to the right of the y-axis, and  appears to remain above the x-axis.

Just a little thought reveals that in fact this must be the case since for all ,  This is due to the fact that , and so any power of  must also be greater than zero.

 

Now, for , we must first note how  and  are related.  When we talk about , we are really just asking what power of  is equal to .  That is, when

, what is ? 

 

For example,  since  implies that   This explains why  is always to the right of the y-axis, since  for all .  Hence,  is not defined for .

 

We say that the domain of , denoted  and the range of , denoted

Similarly,  and .

 

Now, , like , is always to the right of the y-axis.

 

 

                     

 

                                            (2)

 

Why?

 

Well, obviously  if , since  is not defined for .

Hence,  and .

 

We also not that  lies between the graphs of  and , but this makes sense because we are simply adding the two respective functions to form .

 

Now consider .

 

 

              

 

                                      (3)

 

Again we see that  and .

But this time the growth of  eventually overtakes .  Just a little thought we understand why this must be the case, since  for all , and  if .

 

What about

 

 

            

 

                                          (4)

 

Well, as expected  and .

 

What can we guess about  and , where .

 

This time  and .

 

 

                                                   (5)

 

Notice:  appears to be very similar to the graph .  Well, we need only note that , and so , the identity function. 

 

In this case, we say that  and , and so .

 

 

 

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