Jadonna Brewton

Fall 2000

Assignment #11

Problem # 2


A summary of

r = 2a sin (kq)


The graph is commonly known as a rose.


k determines the number of petals. If k is

ODD: k petals

k is congruent to 1 mod 4: the axis petal is on the positive y-axis.

k is congruent to 3 mod 4: the axis petal is on the negative y-axis.

EVEN: 2k petals


a determines the radius of the rose. The radius of the rose is 2a.


If either, a or k is negative, the graph is reflected about the x-axis. If BOTH a and k are negative, then the graph is the same as if both were positive.


Describing the graph

r = 2(3) sin (5q): A rose with 5 petals and a radius of 6. The axis petal is on the positive y-axis.

r = 2(-3) sin (5q): A rose with 5 petals and a radius of 6. The axis petal is on the negative y-axis.

r = 2(3) sin (-5q): A rose with 5 petals and a radius of 6. The axis petal is on the negative y-axis.

r = 2(5) sin (15q): A rose with 15 petals and a radius of 10. The axis petal is on the negative y-axis.

r = 2(-5) sin (15q): A rose with 15 petals and a radius of 10. The axis petal is on the positive y-axis.

r = 2(5) sin (-15q): A rose with 5 petals and a radius of 6. The axis petal is on the positive y-axis.

r = 2(7) sin (4q): A rose with 8 petals and a radius of 14.

r = 2(-7) sin (6q): A rose with 12 petals and a radius of 14.

 


Other equations in write-up # 11

OTHER WRITE-UPS

RETURN TO JADONNA'S MAIN PAGE