Assignment # 3

by Shannon Umberger


Some Different Ways to Examine
ax2 + bx + c = 0

by

James W. Wilson and Shannon M. Umberger
University of Georgia

 

It has now become a rather standard exercise, with available technology, to construct graphs in order to consider the equation

ax2 + bx + c = 0,

and to overlay several graphs of

y = ax2 + bx + c

for different values of a, b, or c as the other two variables are held constant. From these graphs, discussion of the patterns for the roots of

ax2 + bx + c = 0

can be followed. For example, if we set

y = x2 + bx + 1

for b = -3, -2, -1, 0, 1, 2, 3, and then overlay the graphs, the following figure is obtained:

We can discuss the "movement" of a parabola as b changes. Notice that the parabola always passes through the same point on the y-axis ( the point (0,1), using the above equation). For b < -2, the parabola intersects the x-axis in two points which have positive x values (i.e., the original equation has two positive real roots). For b = -2, the parabola is tangent to the positive x-axis, and so the original equation has one positive real root (at the point of tangency). For -2 < b < 2, the parabola does not intersect the x-axis; therefore, the original equation has no real roots (i.e., the roots are imaginary). Similarly, for b = 2, the parabola is tangent to the negative x-axis (so the original equation has one negative real root), and for b > 2, the parabola intersects the x-axis twice (so the original equation has two negative real roots).

Now consider the locus of the vertices of the set of parabolas graphed from

y = x2 + bx + 1.

We can show that the locus of the vertices is the parabola which has the equation

y = -x2 + 1.

The figure below shows the original graph plus the graph of the locus of the vertices. What can you generalize?


Graphs in the xa plane

There are other ways to examine the roots of a quadratic equation by examining the graph. One way is to graph in the xa plane instead of in the xy plane. This simply means that we will substitute y for a into a quadratic equation and then graph.

Let us consider the equation

ax2 + x + 1 = 0.

Now we will graph this relation in the xa plane. To do this, we need to graph the equation

yx2 + x + 1 = 0.

We obtain the following graph:

If we take any particular value of a, and overlay the equation y = a on the graph, we add a line parallel to the x-axis. If the line intersects the curve in the xb plane, the intersection points correspond to the roots of the original equation for that value of a.

Take a look at the following figure. For a = 2, the equation y = 2 is graphed in green. For a = 0.25, the equation y = 0.25 is graphed in blue. And for a = -2, the equation y = -2 is graphed in purple.

We can see on this single coordinate plane that we get no real roots of the original equation when a > 0.25, one negative real root a = 0.25, two negative real roots when 0 < a < 0.25, and one positive real root and one negative real root when a < 0.


Graphs in the xb plane

Now, instead of graphing in the xy plane, we will graph in the xb plane. This simply means we will substitute y for b into a quadratic equation and then graph.

Consider again the equation

x2 + bx + 1 = 0.

Now graph this relation in the xb plane. To do this, we need to graph the equation

x2 + yx + 1 = 0.

We obtain the following graph:

If we take any particular value of b, and overlay the equation y = b on the graph, we add a line parallel to the x-axis. If the line intersects the curve in the xb plane, the intersection points correspond to the roots of the original equation for that value of b.

Take a look at the following figure. For c = -3 and c = 3, the equations y = 3 and y = -3 are graphed in green. For c = -2 and c = 2, the equations y = -2 and y = 2 are graphed in blue. And for c = -1 and c = 1, the equations y = 1 and y = -1 are graphed in purple.

It is clear on this single coordinate plane that we get two negative real roots of the original equation when b > 2, one negative real root when b = 2, no real roots when -2 < b < 2, one positive real root when b = -2, and two positive real roots when b < -2.

Now, consider the case when c = - 1 rather than + 1. Therefore, the equation

x2 + yx - 1 = 0

graphed (in turquoise) below in the xb plane, looks like this:

What can you deduce about the roots of the equation

x2 + bx - 1 = 0

for different values of b by examining the above graph?


Graphs in the xc plane

Finally, instead of graphing in the xy plane, we will graph in the xc plane. This simply means we will substitute y for c into a quadratic equation and then graph.

In the following example, consider the equation

x2 + 5x + c = 0.

To graph this relation in the xc plane, we need to graph the equation

x2 + 5x + y = 0.

We obtain the following graph:

If the equation is graphed in the xc plane, it is easy to see that the curve will be a parabola. If we take any particular value of c, and overlay the equation y = c on the graph, we add a line parallel to the x-axis. If the line intersects the curve in the xc plane, the intersection points correspond to the roots of the original equation for that value of c.

In the following figure, for c = 1, the graph of y = 1 is shown in green. For c = 6.25, the graph of y = 6.25 is shown in blue. For c = -1, the graph of y = -1 is shown in turquoise. And for c = 0, the graph of y = 0 is graph in purple (partially hidden by the x-axis).

We can observe that there is only one value of c where the equation will have one real root: at c = 6.25. For c > 6.25 , the graph equation will have no real roots. For c < 6.25 the equation will have two roots; more specifically, both roots are negative for 0 < c < 6.25, one negative and one 0 when c = 0, and one negative and one positive when c < 0.


Send e-mail to Dr. Jim Wilson at jwilson@coe.uga.edu

or to Shannon Umberger at umbie51698@aol.com


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