Problem:
Number Concepts-Integers (InterMath)

In a class of 22 students, eight receive an 84, 10 receive a 92, and 2 receive a 96 on the last test. If the class average was 90, what are possible scores for the other two students?

 

Solution:

t= test scores

22 * t = 90 (22)

22 * t = 1980

(8*84) + (10*92) + (2*96) + x + y = 1980

1784 + x + y = 1980

x + y = 196

Therefore, the average of the other two students' test scores must equal 98.

Avg (x + y) = 98

The possibilities for the two students' test scores are:
100 and 96
99 and 97
98 and 98



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