Assignment 2

Problem #6

Heather Robinson

EMAT 6680, Fall 2003

 

 

0.  The graph of y = 2x2 + 3x – 4 is graphed below.  This is a parabola pointing upward

     with a vertex at (–1, -5). 

 

1.  Replacing each x with (x – 4) maintains all the properties of the original graph, but

     moves the vertex of the parabola to (3.25,-5.125). 

 

 

 

 

 

 

 

 

 

 

 

 

 

2.  To move the graph into the second quadrant, the equation of the parabola must be

     rewritten as…  2(x + 4)2 + 3(x + 4) + 4.  The vertex of this new parabola is (-4.75,

     2.875). 

 

 

 

 

 

 

3.  To produce a graph that is concave down with the same vertex as #2, the equation of 

     the parabola must be rewritten as… -2(x + 5.5)2 + 3(x + 5.5) + 1.75. 

 

 

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