EMAT 6700- Instructional
Unit
Geometry
Objective: To enhance student
learning through interactive lesson plans using technology. To have students
produce geometric formulas using technology. To have students generate concurrencies
using technology. To further advance students knowledge of Geometer’s
Sketchpad.
Prerequisites: Students do not need to
be familiar with Geometer’s Sketchpad. They should understand and be familiar
with the definitions of shapes such as triangles, circles, and rectangles
before beginning this lesson. The entire lesson plan requires a computer lab
setting.
Lesson Plan:
In this first section students produce the equation of a circle
by exploring circles in Geometer’s Sketchpad.
Students are asked to follow these directions as they explore.
Color of Circle |
|
Radius |
RED |
-3,-2 |
2 |
BLUE |
7,3 |
√10 |
GREEN |
2,2 |
1 |
YELLOW |
-4,2 |
√2 |
PURPLE |
3,-3 |
2 |
Appropriate
amount of time is given here for students to explore this relationship.
In the second section students generate shapes in GSP. As an
introduction students would construct a rectangle in order to learn how to
construct perpendicular and parallel lines.
Constructing a
rectangle:
Here again students are given the opportunity to explore and
construct shapes. They are encouraged to work with others. Eventually the
option of rotation under the transformation menu is introduced. Also if the
idea of creating these shapes within a coordinate system is suggested students
need to understand its limitations. You cannot drag only one point in order for
the shape to remain a square.
In the third section students
generate concurrencies in GSP. Students would begin by exploring sets of lines
in triangles.
When
three or more lines meet at a single point, they are said to be concurrent. The
following facts are true for every triangle:
The
medians are concurrent; they meet at a point called the centroid of the
triangle. (This point is the center of mass for the triangle. If you cut a
triangle out of a piece of paper and put your pencil point at the centroid, you
would be able to balance the triangle there.)
The
perpendicular bisectors are concurrent; they meet at the circumcenter of the
triangle. (This point is the same distance from each of the three vertices of
the triangles.)
The
perpendicular bisectors are concurrent; they meet at the circumcenter of the
triangle. (This point is the same distance from each of the three vertices of
the triangles.)
The
altitudes are concurrent; they meet at the orthocenter of the triangle.
The
angle bisectors are concurrent; they meet at the incenter of the triangle.
(This point is the same distance from each of the three sides of the
triangles.)
Triangles
are the only figures where all these concurrencies always hold.
Homework Problem: Recall that the centroid is the center of mass of a geometric
figure. How could you construct the centroid of a square?
Solution: One can use a straightedge to construct the two diagonals of
the square. The centroid is the point of their intersection. Or one can
construct the perpendicular bisectors of two consecutive sides of the square.
The intersection of these bisectors is the same centroid.
In this fourth section of the lesson plan students would be given an
entire period to explore the following problem.
In Class Problem: Draw five quadrilaterals Use one quadrilateral for each
construction below.
Do these constructions with a
few different quadrilaterals. Don't use only cases like squares and rectangles.
Record any observations about the constructions above. How is this different
from what you saw with triangles?
Solution: For some quadrilaterals (specifically those which can be
inscribed in a circle), the concurrency of perpendicular bisectors holds. For
all quadrilaterals, the midlines come in pairs that are parallel. For some
quadrilaterals (specifically those which can have a circle inscribed in them),
the angle bisectors are concurrent.
In this fifth section students continue their exploration of
triangle centers with the Nagel point and the Gergonne point.
Constructing
a line through the center of the circle and perpendicular to any of the lines
the circle will be tangent to will give us the defining point. Now that we have
a center and a defining point we can construct the circle.
NOTE:
The hide option under the Display menu can be used to unclutter
the screen and hide any lines that may interfere with future constructions.
The
point constructed is the Nagel point.
Again
constructing a line through the center of the circle and perpendicular to any
of the segments the circle will be tangent to will give us the defining point.
This
point constructed is the Gergonne point.
Homework: Find at least one more triangle center or line and find how to
construct it in class tomorrow. Be ready to present your find to the class.