EMAT 6680

FALL 1998

ASSIGNMENT 11

by

Chris McCord


Problem:

Investigate (vary a, b, and k):

r = a + b cos(kt) and r = a + b sin(kt).


Limacons

Limacons ("Lee-ma-sahn") have the form:

r = a + b cos(t) and r = a + b sin(t), where a,b are nonzero real numbers.

Let's look at r = 1 + cos(t)(blue) and r = 1 + sin(t) (magenta):

These are commonly called cardioids. They are one type of Limacon.

Notice that r = 1 + cos(t) is a 90 degree rotation of r = 1 + sin(t).

What does r = 1 - cos(t) look like?

This is simply a reflection about the y-axis. This was expected since we graphed r = a + -f(t) ; instead of r = a + f(t).

Click here to see a movie of r = 1 + cos(t) and r = 1 + sin(t).

Let's look at r = 0.5 + cos(t) (blue), r = 0.5 + 0.5 cos(t) (magenta), and 2 + cos(t) (red):

Notice that the magenta curve is a cardioid (in fact it is 0.5(1 + cos(t))).

But the blue curve is different. This is sometimes referred to as a limacon with an inner loop.

The red curve is different also. It appears to flatten on one side. Sometimes this is considered a convex limacon.

Let's look what happens when we make "a" larger or smaller for r = a + b cos(t):

Magenta (a = 0.5,b = 1); Blue (a = 0.25, b = 1)

As "a" gets larger, the outer loop gets larger and the inner loops becomes smaller. The reverse is true as "a" gets smaller.

Let's look at r = 1.5 + cos(t):

This is a dimpled limacon.


Now, what happens as "k" is varied:

We'll start with k = 0; a = 0.25, b = 1, c 1.5:

r = a + b cos(kt) (blue); r = c + b cos(kt) (magenta);

r = b + b cos(kt) (red)

Now, let's look at k = 1; a = 0.25, b = 1, c 1.5:

r = a + b cos(kt) (blue); r = c + b cos(kt) (magenta);

r = b + b cos(kt) (red)

Now, let's look at k = 2; a = 0.25, b = 1, c 1.5:

r = a + b cos(kt) (blue); r = c + b cos(kt) (magenta);

r = b + b cos(kt) (red)

Now, let's look at k = 3; a = 0.25, b = 1, c 1.5:

r = a + b cos(kt) (blue); r = c + b cos(kt) (magenta);

r = b + b cos(kt) (red)

 

Now, let's look at k = 4; a = 0.25, b = 1, c 1.5:

r = a + b cos(kt) (blue); r = c + b cos(kt) (magenta);

r = b + b cos(kt) (red)

 

Now, let's look at k = 5; a = 0.25, b = 1, c 1.5:

r = a + b cos(kt) (blue); r = c + b cos(kt) (magenta);

r = b + b cos(kt) (red)

Any conjectures? Is there anything similar to what happens as "k" is varied for the curve r = cos(kt) or r = sin(kt)?

Try graphing them and see what happens.

Click here to see a movie of these graphs.


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