Trial XML Document

Math:

The distance between (x₁, y₁) and (x₂, y₂) is d = $\sqrt{(x{1}_{}-x{2}_{}){}^2+(y{2}_{}-y{2}_{}){}^2}$ .

Suppose we want to find t$$ he distance between ($\frac{1}{2}$ , 5) and (-3, $\frac{5}{3}$ ). So,

d = $\sqrt{(\frac{1}{2_{}}-(-3\left)\right){}^2+(5-\frac{5}{3_{}}){}^2}$ = $\sqrt{\left(\frac{49}{4}\right)+\left(\frac{100}{9}\right)}=\sqrt{\frac{841}{36}}=\frac{29}{6}.$

This is the end of the trial.