Then I moved the point P on the circumcircle of ABC:
Click the image to download a GSP file that contains an animation for
this case. Notice that there are points on the circumcircle for which the
degenerated triangle coincides with each of the sides. What is the length
of the line? It must be less than or equal to the diameter of the circumcircle
(obviously it can be larger!) When is the line equal to the diameter of
the circumcircle? When does it have the same lenght as the sides of the
triangle ABC?
If the pedal point is inside the triangle or on the sides, the triangle
RST will be inscribed in the triangle ABC; check the following animation;
the pedal point P is moving along the side AB (and beyond) of the original
triangle:
Incenter, I: couldn't find something special. Although the triangles seem to be similar, observe that the line trough RS is not parallel to BC. Double click to download an animation file, and check in it different triangles ABC.
Circumcenter, K: (Double click to download an animation; check for different triangles ABC)
In any case the pedal triangle RST is similar to ABC. ST is parallel to AC, TR is parallel to AB and RS is parallel to BC. Recall that by construction K is in the intersection of the perpendicular lines to the midpoint of the sides!
Centroid, G: I couldn't find anything special. Notice that the line Sr is not parallel to the line BC. (Double click to download an animation; check for different triangles ABC
Orthocenter: Nothing special. Double click and check for different triangles ABC; What happens when H is outside ABC?
Double click the image and download a file to check for different radius
and different triangles. Can you tell what the focus of the ellipses are?
We just discovered that if the circle is the circumcircle, we get a line.
This is called the Simson line. The tracing of the midpoints yield again
ellipses:
In this case the vertices of ABC and of RST belong to the ellipses!
If the circle has a radius less than the radius of the circumcircle we get:
We got also ellipses. But for sure you must have noticed that the ellipses
are in some sense "oriented". is there any relationship between
the axis ellipses and some lines of the triangle? When the circle is bigger
than the circumcircle the angle bisectors correspond to the longer axis
of the ellipse. This does not happen for the case in which P traces the
circumcircle:
And it seems to hold also for a circle smaller than the circumcircle:
You need to take a closer look to see that this is not true!
Animating the pedal point on the circumcircle, and connecting P to the
orthocenter, we get a new line (the pink one):
It seems that the Simson line divides the line HP in a half. But this is not true. Check in the following animation that the ratios are not (always) in proportion 2:1.
Notice that the ratio is a value very near to 2; nevertheless it is not 2, although the sum of the ratios is 4. But this is not true for ALL the cases; There are points P on the circumcircle for which the sum of ratios is greater thatn 2. Check what happens for P near the circumcenter K, or near to the vertices of ABC. Notice that more than two ratios are nedded because the Simpson line is a degenerated triangle, so it is formed by tree different lines!
So the Simson line is not divided in two equal parts.
Now consider the trace of the point of intersection between the two lines:
Notice that when the orthocenter is inside the triangle we get a circle
that is tangent to one side of the triangle. When the orthocenter is outside
the triangle, the circle is discontinuous. Also note that there are smal
"jumps" in the circles. They correspond to the cases in which
P is approaching to the vertices of the triangle. Click
here is you want to download an animation and test different triangles
ABC.