Tangent Circles by Emily Kennedy Consider two circles--one with center A and radius R (call it Circle A), and another with center B and radius r (call it Circle B). Without loss of generality, say R ≥ r. Also, assume Circles A and B are not tangent to each other. Let P be a point on Circle A. We want to construct a circle, Circle C, that is tangent to Circles A and B such that Circle B lies entirely inside Circle C, like this: Let C be the center of this tangent circle, and let Q be its point of tangency with Circle B (we will have to determine the locations of Q and C). Then and are radii of Circle C, so we must have CQ = CP. (*) Let K be the point on such that AK = R - r and KP = r. Then, from (*), we have CQ = CP  CB + BQ = CK + KP  CB + r = CK + r  CB = CK So ΔCBK is isoceles: Thus, C lies on the perpendicular bisector of . So the tangent circle we want is simply the circle through P, with center C. In this GSP file, you can trace the center C of the tangent circle as P moves around Circle A. What do you see? Move Circles A and B around and adjust their radii. Try as many cases as you can think of, and make some conjectures before clicking here to continue.