In order to move the vertex of the graph into the second quadrant, we will have to move the original graph up and to the left. Notice that we replaced x with (x+5) in order to get our horizontal shift to the left 5 units. The value 6 was chosen in order to move the graph 6 units vertically. If we add 6 to both sides of the red equation, we can see that we are effectively adding 6 units to every y-value. It is a little more friendly looking to leave the 6 on the left side of this equation and it makes it easy to identify the vertical translation.


What is the smallest vertical translation value that we could have chosen to put our graph in the second quadrant?

Is the red graph truly in the second quadrant? Tell me something about its domain in order to support your answer.