**In order to move the vertex of
the graph into the second quadrant, we will have to move the original
graph up and to the left. Notice that we replaced x with (x+5)
in order to get our horizontal shift to the left 5 units. The
value 6 was chosen in order to move the graph 6 units vertically.
If we add 6 to both sides of the red equation,
we can see that we are effectively adding 6 units to every y-value.
It is a little more friendly looking to leave the 6 on the left
side of this equation and it makes it easy to identify the vertical
translation.**

**What is the smallest vertical
translation value that we could have chosen to put our graph in
the second quadrant?**

**Is the red graph
truly in the second quadrant? Tell me something about its domain
in order to support your answer.**