Keep in mind that the curve above is
over the interval
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.
That is, if the interval was

then only the bottom half of the circle
would be the curve. See Figure 2 below.

This graph was created by
Graphing
Calculator 3.2.
Figure 2
If the interval is
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, then
the curve would start at (1,0) and create 2
½
revolutions and end at (-1,0). The list below shows the values of x and
y that correspond to multiples
of π/4 for the
parameter t.
t |
x =
cos t |
y = sin
t |
0 |
1 |
0 |
π/4 |
1/√2 |
1/√2 |
π/2 |
0 |
1 |
3π/4 |
-1/√2 |
1/√2 |
π |
-1 |
0 |
5π/4 |
-1/√2 |
-1/√2 |
3π/2 |
0 |
-1 |
7π/4 |
1/√2 |
-1/√2 |
2π |
1 |
0 |
9π/4 |
1/√2 |
1/√2 |
5π/2 |
0 |
1 |
11π/4 |
-1/√2 |
1/√2 |
3π |
-1 |
0 |
13π/4 |
-1/√2 |
-1/√2 |
7π/2 |
0 |
-1 |
15π/4 |
1/√2 |
-1/√2 |
4π |
1 |
0 |
17π/4 |
1/√2 |
1/√2 |
9π/4 |
0 |
1 |
19π/4 |
-1/√2 |
1/√2 |
5π |
-1 |
0 |