Squaring the Circle – Ruler and Straight Edge Approximations

           

Given a circle, we want to construct a square having the same area as the circle.  Suppose the radius of the given circle is one.  Then the area of the circle is p.  The area of the desired square, then, is also p.  Therefore, each side of the square that we want to construct will have a length of Öp.  In order to construct such a square, we need to be able to construct a segment of length p.  We cannot construct a segment having a length equal to exactly p (see the discussion of the proof), but we can construct some pretty good approximations.  Here are two examples of approximations:

 

  1. p » Ö(40/3 – 2Ö3) » 3.14153
  2. p » 355/113 = 3 + 16/113 = 3 + 42/(72 + 82) » 3.1415929

 

These approximations are from the following web page:  http://www.uwgb.edu/dutchs/PSEUDOSC/SquareCirc.htm

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