ASSIGNMENT 11

BY

SHADRECK CHITSONGA

 

CONICS-USING POLAR EQUATIONS

 

Before going through this write up, please open this LINK to have an idea of what we will be discussing. We will start here by looking at the parabola.

 

 

 

 

Figure 1

 

This is a parabola whose axis of symmetry is in the x-axis. It opens up towards the negative x-axis. This is so because the coefficient of y is negative.  Its vertex is at (1,0) and crosses the y-axis at (0,2) and (0,-2).

Here is another graph. Is this a parabola as well? How do you know?

 

 

Figure 2

 

One thing that might be obvious is that the two curves in figure 1 and figure 2 look alike, but the functions used to draw them do not look  the same. The first curve is drawn in the rectangular coordinate system, while the second curve is drawn in polar coordinates.

In this write up we will investigate why this is the case.

 

We will start by looking at the construction of a parabola in GSP. There are a number of points we want to highlight.

The diagram in figure 3 shows the construction of a parabola in GSP. This construction uses the locus definition of a parabola.

A parabola is defined as the set points in the plane equidistant from a given line called directrix and a point P not on the line.

Fo is called the focus of the parabola.

Using this definition it is obvious why PFo = PQ.

 

 

 

Figure 3

 

We will use this diagram to try to manipulate a few things.

By construction we know that PQ = AB.

Now let the distance PFo be r and FoB  be k. We can write PQ = AFo +FoB

Now let us express PFo in terms of angle

PFo  = 

Letting PFo be r , we can now write AFo = r cos . This means that we can write PQ = k + r cos   (i)

We will now introduce the terminology used in conics.

The ratio  is called the eccentricity of the curve.  Lower case e is used to represent the eccentricity.

Now using (i) and knowing that we let PFo be r, we can write

 =

This means that   = e,

Equivalently  (ii)

Now let us go back to the curve that we drew in polar coordinates. The equation for the curve is  (iii).

Are there any similarities between (ii) and (iii)?

What about if write (iii) as .

Now we can see that the two equations are identical; k = 2 and e  = 1.

Remember e is the eccentricity. But we know from the definition of the parabola that PQ = PFo, and that = e. this then means that  = e =1

Now that we have established that the function  or more generally  gives a curve that is a parabola.

 

There are still a few things we can explore here. For example we can do the following:

1. What effect does changing the value of k have on the curve?

2. What happens when we introduce a negative in the denominator instead of

    a positive sign?  I.e. use  ( 1- e cosq)

   To answer these questions, let us look at the curves in figure 4

 

Figure 4

 

What observations have you made? Did you notice the following?

1. Putting a negative sign in the denominator, changes the orientations of the

    parabola. It is now opening towards the positive x-axis.

2. As the value of k increases the parabolas get wider.

3. The value of k determines where the parabola cuts the y-axis. The curve

    crosses the y-axis at (0,-k) and (0, k).

4. In our example here all the curves share the same line of symmetry.

 

One question that one might have is; Is it possible to have parabolas that have their axis of symmetry as the y-axis?  With the function that includes the cosine of an angle we have seen that the parabolas formed have their lines of symmetry in the x-axis. Now let us try the functions that have sine of an angle. Refer to figure 5.

 

Figure 5

 

Just as we did with the curves involving the cosine we can also talk about a few things here.

1. Leaving all the things the same changing from a cosine to a sine

     gives a parabola whose axis of symmetry is now the y-axis.

2. If there is –sin q in the denominator the curve is concave upwards, while

    if it is  +sin q, the curve is concave downwards.

3. Just as before the value of k determines where the graph crosses one of

    the axes. In this case the graph crosses the x-axis at (-k, 0) and (k , 0).

 

For  hyperbolas go to this LINK. For ellipses go to this LINK