# Pedal Triangles

November 23, 2010

This investigation looks at some properties of pedal triangles and makes use of Geometer SketchPad.

## 1. The Pedal Triangle

A pedal triangle is defined as the projection of some point onto a triangle.

Here is the definition on Wikipedia.

Here is the definition on Wolfram Mathworld.

This is what it looks like:

Figure 1: Pedal Tiangle of point P on triangle ABC

We find the pedal triangle by projecting point P onto each side of the triangle. Projection is done by constructing a perpendicular line onto some side, passing through P:

This process can be repeated for this pedal triangle again in the same way. Our problem look at repeating this process until we have a pedal triangle of a pedal triangle of a pedal triangle, known as the 3rd pedal triangle of ABC.

## 2. The Conjecture and its Construction

We want to show:

The third pedal triangle is similar to the original triangle ABC

The proof is in showing that each respective angle of the two triangles are equal eg.

Figure 1: Two similar triangles

The construction is given in the video below, it makes use of a tool that draws a pedal triangle once its been given a point and the three vertices of the triangle. The tool can be downloaded here.

 So we need to show that triangle LJK is similar to ABC.

## 3. Building Blocks of the Proof

Here are some important building blocks (B) we will be using for the proof:

• B1: The hypotenuse of right-angled triangle is the diameter of its circumcircle

• B2: All angles subtended by the same arc, are equal.

## 4. Proof of the Conjecture

Figure 4.1: The problem

 To show that triangle LJK is similar to ABC.

This is how we go about it:

Figure 4.2: ABC and EFG

Here in Figure 4.2 we simplify the problem by only showing the construction of the first two triangles. Additionally, we construct PC, PF and PD. Recall that PF is perpendicular to BC and PD to AC by construction (because that is the definition of the projection of P onto BC and AC).
Figure 4.3 Using B1

We use the building block B1 in constructing this circle: PC is the diagonal of the circle though points P, F and C. D also lies on this line by sharing PC as a base with PFC and having right angle PDC.

Figure 4.4: Using B2

By using the building block B2 we know that angle PFD equals angle PCD by the subtended arc of PD.

Figure 4.5: Using B2 again

Using B2 again, we also show angle FCP equal to angle FDP.

Figure 4.6: Naming the angles

We split angle ACB up into two parts and call them lowercase a and b respectively.

Figure 4.7: Naming all angles

In the same way as figure 4.6, we split angle ABC and angle CAB into two parts and apply the same reasoning to get angles a though f into the first pedal triangle.

Figure 4.8 The first pedal triangle

Let's have a closer look at figure the first pedal triangle.

Figure 4.9: Only the first pedal triangle.

We will go to work on this triangle using the same reasoning as with the main triangle.

Figure 4.10: The second pedal triangle

This is the second pedal triangle constructed inside the first.

Figure 4.11: Using B1 and B2

Figure 4.12: B1 and B2 applied to all angles.

Figure 4.13: The second pedal triangle

4.14: The third pedal triangle inside the first

Figure 4.15 Using B1 and B2

Figure 4.16: Using B1 and B2 for all angles

Figure 4.17: The third pedal triangle

Finally, by comparing with Figure 4.7, we have

• angle JKL = a + b = angle ACB
• angle KJL = c + d = angle CBA
• angle JLK = e + f = angle BAC

Therefore:
 Triangle JKL is similar to triangle CBA.

In closing

Remember that when we work with proofs and conjectures, we try to find all applicable building blocks that can be applied to the problem and then, systematically,  sift out as much information as possible using the given facts and also the comparisons that can be made using what we know.

There are usually many ways to solve a given problem and reaching dead-ends are sometimes vital in reaching a solution.